Question

c3h8+502=3co2+4h2o how much volume of co2 liberated when 2 moles of c3h8 react with 2moles of o2​

Answer 1

Answer: From the equation it is clearly visible that 1 mole of C3H8 reacts with 5 moles of O2 so O2 is the limiting reagent here.

Now there are 2 moles of O2 so only 0.4 moles of C3H8 will react.

One mole of C3H8 gives 3 moles of CO2 show 0.4 moles of C3H8 will give 1.2 moles of CO2 gas.

Now the volume of 1 mole of CO2 gas is 22.4 litres so the volume of 1.2 moles will be 1.2 * 22.4 = 26.88L