Question

C3h8 + 5O2 gives rise to 3CO2 + 4H2O
what is the volume of carbon dioxide
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Answer 1

Answer:

From the given data we can deduce that C3H8 + 5O2 -> 3CO2 + 4H2O . Again, we can say that equation as 2C4H10 + 13O2 -> 8CO2 + 10H2O . Since the number of moles of propane is 1 and it gives 3 moles CO2. So, we know that the 60 ml of propane will give 3 X 60 = 180 ml CO2

Explanation:

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Answer 2

First, we need to convert grams of each reactant to moles.

When we convert grams to moles or moles to grams, we use molar mass.

The molar mass of O2 is 16.0g/mol, C3H8 is 44.1g/mol

=>O2 : 98.0g / (16.0 g/mol) = 6.13 mol

=>C3H8 : 7.00g / (44.1g/mol) = 0.159 mol

Now, we need to find which one is limiting reactant.

From balanced equation, we get 1:5 ratio between C3H8 : O2.

If we assume C3H8 is limiting reactant, we will consume 0.159 moles (all) and (0.159moles × 5 =>0.795) moles of O2. Since we have enough amount of O2 for this reaction, our assumption was correct.

Therefore, C3H8 is limiting reactant and O2 is excess reactant.

Then, we take ratio between C3H8 : CO2 to find the number of mole of CO2 produced.

They have 1:3 ratio, so we will get (0.159 × 3 = 0.477)moles of CO2.

For final answer, we need to convert moles to grams.

The molar mass of CO2 is 44.01g/mol.

=>0.477mol × 44.01g/mol

=>21.0g of CO2

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