Question

C3H8+ Br2 → A (Major)
C2H5ONa+A------>B
The compound B is
(a) CH3-CH2-CH2OC2H5
(b) (CH3)2CH-CO-OC2H5
(c) CH3CH=CH2
(d) CH3-CHBr-CH3​

Answer 1

A and b are given above. A as bromopropane

Answer 2

The final product formed, B, is $CH_{3}CH=CH_{2}$.

• In the first reaction, propane is reacted with bromine. This is a substitution reaction of alkanes and the major product formed is 2-bromopropane.
• Thus A is $(CH_{3}) _{2} CHBr$.
• Reaction of bromopropane with sodium ethoxide is an elimination reaction, where bromine is removed forming 1-propene.
• Thus B is $CH_{3}CH=CH_{2}$.