Question

C3H8(g) + 5O2(g) –> 3CO2(s) + 4H2O(g)

Given the equation above, how many moles of H2O gas are produced when 6.5 moles of propane (C3H8) react with excess oxygen?

Answer 1

Answer:

The molar masses of propane and water are 44 g/mol and 18 g/mol respectively.

44.0 grams of propane corresponds to 1 mole of propane.

According to the balance chemical equation, C

3

H

8

(g)+5O

2

(g)→3CO

2

(g)+4H

2

O(l),

1 mole of propane gives 4 moles of water.

Thus, the combustion of 44.0 g (1 mole) of propane will give 4 moles of water.

Mass of water obtained =4×18=72.0 g.