C6H₁2O6(aq) + O₂(aq) + H₂O(1)→CO₂ (aq) + H₂O (1) + Energy
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Answer:
O
2
x−
+2H
2
O→4OH
−
+3O
2
In RHS the total charge is −4
so in LHS also the the charge should be −4
so x=−4
now the oxidation state of O is
2x=−4
x=−2
so it is oxide
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