Question

C6H5-CH=CH2+HBr in presence of peroxide

Answer 1

• When C₆H₅-CH=CH₂ (2- phenyl ethene) reacts with HBr in the presence of peroxides then C₆H₅CH₂CH₂Br (1-bromo 2-phenyl ethane) will be formed.
• Addition of HBr in the presence of peroxides yields anti Markovnikov's product as a major product.
• Mechanism initiated by the homolytic cleavage of peroxides.
• Then bromine free radical is formed which attacks into the ethene and yields anti Markovnikov's product.

Regards

Answer 2

Explanation:

1. for exam like this reaction is very important we can refer like sandmeyer,diazodisation,wurtz, wurtzfitting,fitting from haloalkens and haloarenes chapter