Chemistry, asked by Nviasjin2552, 9 months ago

C6H5CH2Cl ,C6H5CH2CH2Cl are treated with aqueous KOH identify the mechanism and product followed by the two compound​

Answers

Answered by pooja303417
1

Answer:

Benzyl chloride | C6H5CH2Cl or C7H7Cl | CID 7503 - structure, chemical ... Molecular Formula: C7H7Cl or C6H5CH2Cl ... These are aromatic compounds containing a benzene substituted at one or more positions.Hope it's help you

Answered by Jasleen0599
0

C₆H₅CH₂Cl on treatment with aqueous KOH forms C₆H₅CH₂OH via SN2 mechanism and C₆H₅CH₂CH₂Cl on treatment with KOH forms C₆H₅CH₂CH₂OH.

- The reaction between C₆H₅CH₂Cl and aqueous KOH takes place as follows:

C₆H₅CH₂Cl + KOH ---> C₆H₅CH₂OH + KCl

- The reaction between C₆H₅CH₂CH₂Cl and aqueous KOH takes place given as under:

C₆H₅CH₂CH₂Cl + KOH ---> C₆H₅CH₂CH₂OH + KCl

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