Question

C6H5CHO + CH3CH2CHO dil.NaOH

Answer 1

Answer:

C6H5-CHO + CH3-CH2-CHO in presence of dil.NaOH, gives out C6H5-CH=CH-CHO + 2H2O.

Answer 2

Dear Student,

◆ Answer -

C6H5-CH(OH)-CH(CH3)-CHO

● Explanation -

When two aldehydes are treated in presence of dil.NaOH, they get added to form a adduct. This is called aldol condensation reaction.

When benzaldehyde (C6H5-CHO) is treated with propanal (CH3-CH2-CHO) in presence of dil.NaOH, an aldol condensation product C6H5-CH(OH)-CH(CH3)-CHO is formed.

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