Question

C6H5NHCH3+NaNO2+HCl this reaction product

Answer 1

Answer:

N-nitroso-Nmethyl amine

Answer 2

Answer: N-nitroso- N-methyl Aniline

$N-Nitroso- N-Methyl\ Aniline$

Explanation:

$NaNO_{2}+HCl\rightarrow HNO_{2}+H_{2}O\\\\C_{6}H_{5}NHCH_{3}+NaNO_{2}+HCl\rightarrow C_{6}H_{5}N(NO)CH_{3}+NaCl$

N-Nitroso- N-methyl Aniline is the reaction product when N-Methyl Aniline reacts with Sodium nitrite and Hydrochloric acid.

Here  N-Methyl Aniline is a secondary amine. 2º-Aryl amines give N-nitrosamine derivatives on reaction with nitrous acid just like aliphatic secondary amines.

The process of the reaction mechanism is given below:

$OH-N=O\ +H^{+}\rightarrow H_{2}O^{+}-N= O\rightarrow N^{+}= O\rightarrow N\equiv O^{+}\\\\C_{6}H_{5}NHCH_{3} +N\equiv O^{+}\rightarrow C_{6}H_{5}N(NO)CH_{3}$