Chemistry, asked by om3006, 5 months ago


C6H6( + 7.502(g) → 6CO2(g)
6CO2(g) + 3H,0 ()
AH = -326.7 kJ
In this reaction, the standard enthalpy of
formation of CO2(g) and H20 g) are -393.5 and
-285.85 kilo Joule\mole-1 respectively calculate
the standard heat of formation of benzene.

Answers

Answered by kundanconcepts800
0

Answer:

- 2892.85 KJ/mol

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