Question

ca
Find the point on the xanaszichoch is equistant
(2,-5) and (-2,9).​

Answer 1

Answer:

Given points A(2,−5) and B(−2,9)

Let the points be P(x,0).

So, AP=PB and AP2=PB2

 ⇒(x−2)2+(0+5)2=(x+2)2+(0−9)2

⇒x2+4−4x+25=x2+4+4x+81

⇒x2+29−4x=x2+85+4x

⇒−4x−4x=85−29

⇒−8x=56

⇒x=−7

Answer 2

Answer:

Hey r u from telangana?