Question

चुम्बकीय क्षेत्र के अनुदिश प्रक्षेपित आवेशित कण का मार्ग कैसा होगा ?​

Answer 1

Answer:

i)

20−20=25−25(1)

Expands to a multiple of 5.

5×4−5×4=5×5−5×5(2)

(5−5) When you come

4×(5−5)=5×(5−5)(3)

4=5(4)

2+2=5(5)

End of proof.

Answer 2

Answer:

Answer:

i)

20−20=25−25(1)

Expands to a multiple of 5.

5×4−5×4=5×5−5×5(2)

(5−5) When you come

4×(5−5)=5×(5−5)(3)

4=5(4)

2+2=5(5)

End of proof.