Ca(OH)2+2NH4Cl→CaCl2+2NH3+2H2O
1) To completely react 37g Ca(OH)2 how many moles of NH4Cl is required?
2) How many moles of NH3 gas will be produced?
3) Determine the mass of NH3 in grams.
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Answer:
1- 1 mole of nh4cl required
2-1 mole of nh3 gas will be produced
3-Mass of nh3 will be 17 grams
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