Question

चार प्रतिरोधक 22, 42, 60 और 80 समानांतर
में जुड़े हैं । वे एक 24V की बैटरी से जुड़े हैं। 60
प्रतिरोधक से गुजरती विद्युत धारा ज्ञात करें।​

Answer 1

Answer:

Given resistances are joined in series 22, 42, 60, 80

Total Resistance = 22+42+60+80 = 204 ohm

Voltage supplied by battery = 24V

In series combination, current remains equal for all resistances.

I = V/R

I = 24/204 = 0.117A

Answer is 0.117A

(Sorry for not replying in Hindi because I don't know how to)

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