चित्र में, PQ वृत्त का व्यास है और O वृत्त का केंद्र व्रत पर स्थित एक बिंदु A से खींची गई स्पर्श रेखा PQ के बढ़े हुए भाग को बिंदु R मिलाती है सिद्ध कीजिए कोण QAR=1/2(कोण90-कोणQRA)
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∠QAR = (1/2)(90° - ∠QRA)
Step-by-step explanation:
∠OAR = 90°
∠OAQ = ∠OAR - ∠QAR
=> ∠OAQ = 90° - ∠QAR
∠OAQ = ∠OQA ( OA = OQ = Radius)
=> ∠OQA = 90° - ∠QAR
∠OQA =∠QAR + ∠QRA
=> 90° - ∠QAR = ∠QAR + ∠QRA
=> 90° - ∠QRA = 2∠QAR
=> ∠QAR = (1/2)(90° - ∠QRA)
इति सिद्धम
QED
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