[Ca2+] in hard water is about 2.0x10-3M. Water is fluoridated with 1.0 g F- per 1.0 x 103 L of water. Will CaF2(s) precipitate from hard water upon fluoridation? Ksp (CaF2) = 5.3 x 10-
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The new acceleration is 12 m/s²
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➤ How to solve ?
A Force is a push / pull upon an object resulting from the people interaction with any of the another object.
Newton's 2nd law stated as F = Ma
Means,
•F acting on an object is equal
⠀⠀⠀⠀⠀to the mass of an object time it's A.
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➤ Solution :
As , F = ma
➨ a = F / m
➨ 2 = F / m
Now , we want to see the value of a produced with 3f respectively
➨ a = F / m
➨ a = F / m/ ²
➨ a = 6 F / m
As we have already got F / m = 2
➨ 1 / 6 a = 2
➨ a = 12 m/s ²
⁖ New Acceleration is 12 m/s ²
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