Question

ca3(po4)2 oxidation no of CA=+ 2 and o=2​

Answer 1

Ca3(PO4)2

Let oxidation no of P be x

2×3+(x+2×4)2=0

6+2x+16=0

22+2x=0

2x=-22

x=-11

Oxidation no of P = -11

Answer 2

The question is incomplete, here is the complete question:

Find the oxidation number of phosphorus for the given compound $Ca_3(PO_4)_2$ given that oxidation number of calcium is +2 and that of oxygen is -2

The oxidation number of phosphorus atom in the given compound is +5

Explanation:

Oxidation number is the number that is assigned to an element when it gains or loose electrons.

If the element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

We are given a chemical compound having formula of $Ca_3(PO_4)_2$

We take the oxidation state of phosphorus atom be 'x'.

Oxidation state of oxygen atom = -2

Oxidation state of calcium atom = +2

Evaluating the oxidation state of phosphorus atom:

$3(+2)+2x+8(-2)=0\\\\x=+5$

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