cable
In figure the uniform gate weighs 300 N and is 3 m wide and 2 m high. It is
In 3m
3 m
supported by a hinge at the bottom left corner and a horizontal cable at the top left
corner, as shown. Find:
2m
(A) The tension in the cable
(B) The force that the hinge exerts on the gate (magnitude and direction).
(Ans.: (A) 225 N, (B) Fx = 225 N, F, = 300 N)
hinge
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Answer:
T = 225N, F hinge = 375 N
Explanation:
In order to undertand the question completely, first see the figure explaining the scenario.
Total torque about the point O is zero
T x2 = mg x 3/2
T = 300 x ¾
T = 225N
Hence the tension in string is 225N
Total Force is also zero;
F hinge + T + mg = 0
F hinge = Mag ( T + mg)
F hinge = √(〖225〗^2+〖300〗^2 )
F hinge = 375 N
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