CaC2+H2O=Ca(OH)2+C2H2
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Answer:
CaC₂ (s) + 2H₂O (l) ⟶ Ca(OH)₂ (s) + C₂H₂ (g)
Explanation:
CaC₂ + H2O ⟶ Ca(OH)₂ + C₂H₂
In this reaction, calcium carbide ( CaC₂ ) reacts with water ( H₂O ) to form calcium hydroxide ( Ca(OH)₂ ) and acetylene ( C₂H₂ ).
Atoms in reactants side:
- Ca = 1
- C = 2
- H = 2
- O = 1
Atoms in products side:
- Ca = 1
- C = 2
- H = 4
- O = 2
By law of conservation of mass, we know that the number of atoms of each element in reactants side must be equal to number of atoms in products side.
In reactants side, 2 hydrogen and 1 oxygen atoms are missing. So to make both sides equal in number of atoms, we multiply H₂O by 2.
CaC₂ (s) + 2H₂O (l) ⟶ Ca(OH)₂ (s) + C₂H₂ (g)
This is the balanced chemical equation.
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