Chemistry, asked by Saurabhk375, 1 year ago

Cacl2 is highly soluble in water while CaF2 is insoluble.Give reason

Answers

Answered by rajputkiyaari
4

HEY MATE HERE IS THE CORRECT ANSWER

The ionic strength as well as the bond length are the important factors that decide the solubility of salts. ... CaF2 is not soluble in water due to extremely high lattice energy.CaCl2 is fairly soluble in water as it's lattice energy is lower compared to CaF2.

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Answered by tushargupta0691
0

Answer:

The ionic strength of a solution is determined by the amount of ion concentration present. It is expressed as I. It has an impact on ion activity.

Explanation:

Salt solubility is mostly determined by two main factors: ionic strength and bond length.

Ionic strength is shown by the interaction of the ions in the solution with the water and other ions. Half of the total concentration of each ionic species is calculated using the ionic strength formula.

Greater is the bond length in a compound, lesser energy is required to break. Thus, higher will be the solubility of that compound in water.

The size of the chlorine anion is greater in CaCl₂. This will result in greater bond length which requires less amount of energy to break. The bond easily dissolves in water as a result. Hence, it is highly soluble in water.

The size of the fluorine anion is smaller in CaF₂. This will result in a shorter bond length which requires a high amount of energy to break. The bond does not dissolve in water as a result. Hence, it is insoluble in water.

Hence, CaCl₂ is highly soluble in water while CaF₂ is insoluble.

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