૨૫૦ ગ્રામ caco3 માં કાર્બન ની પરમાણું સંખ્યા કેટલી હશે?
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Explanation:
Chemical reaction involved is:
CaCO 3→CaO+CO 2
Molar mass of CaCO3=40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO3
produces 1 mol of CO 2
i.e. 22.4 L at STP.
∴50 g CaCO3 will produce
22.4/100×50=11.2 L CO 2 at STP.
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