Question

CaCO3 + 2HCl → CaCl22+ H20 + CO2 given that Hcl is 20% w/w so, find total amount of Hcl that will react with 100g of CaCO3​

Answer 1

Answer:

Given 100g if CaCO3

mole = given wt/atomic wt

==> 100/100

==> 1 mole

1 mole CaCO3 reacts with 2 Mole HCl

wt. of HCl = 2 × 36.5 = 73g

let the weight of total HCl be x

==> pure HCL = 20% of x

==> x × 20/100 = 73

x = 365g