Question

caco3 + 2hcl find mass of cacl2​

Answer 1

Answer:

250 ml of 0.76M HCl is taken.

We know that :-

Therefore:-

Mass of calcium carbonate taken = 1000g

Molar mass of CaCO3 = 100g

Number of moles will be 10

Now,

Clearly ,The limiting Reagent is HCl here

Molar mass of caCl2 = 111 g

Now:-

2 mole of HCl produces 1 mole of CaCl2

1 mole of HCl will produce 0.5 mole of CaCl2

0.19 mole of Hcl produces 0.095 mole of cacl2

Mass of Calcium Chloride Produced will be :-

= 111*0.095.

= 10.545.