Question

CaCO3 + 2HCl -> CaCl2 + CO2 + H2O What mass is required to react completely with 25ml of 0.75M HCl ?

Answer 1

hola frnd!!!

here iz ur anzzz.....

1000 ml of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5g = 24.375 g

therefore, Mass of HCl in 25ml of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g

From the given chemical equation,

CaCO3 (s) + 2HCl (aq) —> CaCl2(aq) + CO2(g) + H2O(l)

2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g

therefore, 0.6844 g HCl react completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g

hope it hlps.... ^_^

# be brainly!!!!

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SAMEERA❤️