Question

Caco3
CaO +
=COrg
(100 g)
(56 gm)
(44 g)
In the above reaction. What is the volume of co2 liberated when 50 gm of calcium carbonate is heated ?​

Answer 1

Answer:

CaCO

3

=

100

50

=

0.5

According to reaction, 1 mole of

CaCO

3

gives 1 mole of

CO

2

.

So 0.5 moles of CaCO

3

will give 0.5 moles of

CO

2

Now at STP 1 mole of any gas = 22.4 L

So 0.5 moles of CO

2

gas = 22.4 × 0.5 = 11.2 L

Explanation:

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