CaCO3 + H2SO4 = CaSO4 + H2O+ CO2 Which substance is reduced and which substance is oxidised in this reaction?
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Oxidation number of elements of Reactant
Ca = +2
C= +4
O= -2
H= +1
S = -6
Oxidation number of elements of products
Ca = +2
C= +4
O= -2
H= +1
S = -6
Since, there is no change in oxidation number, so this reaction is neither oxidation nor reduction reaction.
It is decarboxylation reaction, CO₂ molecule evolved.
Ca = +2
C= +4
O= -2
H= +1
S = -6
Oxidation number of elements of products
Ca = +2
C= +4
O= -2
H= +1
S = -6
Since, there is no change in oxidation number, so this reaction is neither oxidation nor reduction reaction.
It is decarboxylation reaction, CO₂ molecule evolved.
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