Question

caco3+ hcl cacl2+co2+ h2o 100 gm of caco3 produces 44 gm of co2 how much amount of co2 is produced when 300 gm of caco3 is used​

Answer 1

$\underline {\boxed {\bold {Question}}}$

• How much amount of CO₂ is produced when 300 gm. of CaCO₃ is used​?

$\underline {\boxed {\bold {Important \: concepts \: to \: be \: remembered}}}$

• CaCO₃(s) → CaO (s) + CO₂ (g)

• $Moles = \frac{Given \: Mass}{Molar \: Mass}$

$\underline {\boxed {\bold {Given \: information}}}$

• 300 grams of CaCO₃ (Molar mass = 100)

$\underline {\boxed {\bold {Answer}}}$

No. of moles of 300 grams of CaCO₃ = 300/100 = 3

∴ 3 moles of CaCO₃ are provided for reaction.

So by comparing stoichiometry coefficient,

1 mole of CaCO₃ → 1 mole of CO₂

So,

3 moles of CaCO₃ → 3 moles of CO₂

$\underline {\boxed {\bold {\therefore \: Moles \: of \: CO_{2} \:= 3 moles}}}$

∴ By mole concept,

Moles × Molar mass = Given mass

∴ Given mass = 3 × 44 = 132 grams.

$\underline {\boxed {\bold { Answer \rightarrow{ \: Amount \: of \: CO_{2}\: produced \: in \: reaction \:= 132 grams}}}}$