Question

caco3 is 90 pure. volume of co2 collected at stp when 10 g of caco3 is decomposed is

Answer 1

Answer:

 Limestone is essentially CaCO3; molar mass of CaCO3 = 100 g/mol 

10 gm of 100% pure would be 10 gm of CaCO3 

90% pure means you have only 9 gms of CaCO3 in the 10gm sample 

9 gms/100gm/mol = 0.09 moles of CaCO3 

When heated 1 mole of CaCO3 yields 1 moles of CO2 

0.09 moles of CO3 will yield 0.09 moles of CO2 

1 mole of CO2 = 22.4 liters 

22.4 liters/mol x 0.09 moles = 2.016 liters