Caco3, reacts with HCl to produce CaCl,,CO2, and H20. The approximate mass (in g) of Caco3
required to react. Completely with 25 ml of 0.75 M HCI is
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Asked on December 30, 2019 by
Srujan Kasyap
Calcium carbonate reacts with aqueous HCl to give CaCl
2
and CO
2
according to the reaction -CaCO
3
(s)+2HCl(aq)→CaCl
2
(aq)+CO
2
(g)+H
2
O(l)The mass of CaCO
3
which is required to react completely with 25 ml of 0.75 M HCl is:
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ANSWER
Eq. of CaCO
3
= Eq. of HCl.
Eq. of HCl =
1000
25×0.75
Eq. of CaCO
3
=
100
2×mass
Mass of CaCO
3
=0.9375g
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What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl? And 25 ml of solutions contains Hcl = 27.375/1000 * 25 = 0.6844 g. 2 mol of HCl (2 × 36.5 = 71 g) react with 1 mol of CaCO3 (100 g).
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