Question

CaCO3(s)  CaO(s) + CO2(g) What volume of CO2 will be liberated at STP by heating 2.5 kg of CaCO3 ?

Answer 1

Answer:

Chemical reaction involved is:

CaCO 3 →CaO+CO2

Molar mass of CaCO3 =40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO3produces 1 mol of CO2

i.e. 22.4 L at STP.

∴50 g CaCO 3 will produce 22.4/100×50=11.2 L CO2at STP.

Answer 2

Chemical reaction involved is:

CaCO 3 →CaO+CO2

Molar mass of CaCO3 =40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO3produces 1 mol of CO2

i.e. 22.4 L at STP.

∴50 g CaCO 3 will produce 22.4/100×50=11.2 L CO2at STP.