Caculate number of moles and molecules of acetic acid present in 22g of it.
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Answer:
no.of mole =0.3667 mol
no.of molecules =2.208×10^23
Explanation:
no.of mole =mass of acetic acid ÷molar mass of acetic acid =22÷60=
0.3667 mol
no.of molecule =0.3667×6.023×10^23= 2.208×10^23
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