Question

caculate the effective mass of a photon of energy 5ev?​

Answer 1

Answer:

lamda = 3.6 angstrom = 3.6 x 10^-10 m.

velocity of photon = velocity of light.

m = h/lamda*v ( from de-brogile's equation)

m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8.

m = 6.626 x 10^-32/10.8.

m = 0.6135 x 10^-32.

m = 6.135 x 10^-33 kg.