Question

caculate the electric potential at a distance 20cm from a point charge 6mC​

Answer 1

Electric Potential ,V = q/r

V = 6 × 10^(-3)/20 × 10^(-2)

V = 0.03 V

Answer 2

Answer:

Explanation:

DISTANCE, R = 20 CM          

                      = 20*10⁻² M

                      = 0.20 M

CHARGE ,Q = 6 MC

                    = 6*10⁻³ C

ELECTRIC POTENTIAL ,V = (1/4π∈)*Q/R

1/4π∈ = 9*10⁹

V = 9*10⁹*6*10⁻³/0.2

V = 9*6*10⁶/2*10⁻¹

V = 9*3*10⁷

V = 27*10⁷ VOLTS .

HOPE THIS HELPS.