Caculate the mass of Noah required to prepared 50ml of n/10 Noah solution
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What is the mass of NaOH that is required to make 500ml of a 0.5M aqueous solution?
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This is a pretty simple question of mole concept and the solution goes like this:
Given:
Volume of NaOH = 500 mL
Molarity of the aqueous solution = 0.5 M
Molar mass of NaOH= (23+16+1)g = 40g
Let the mass of NaOH be x.
Now , according to formula number of moles of a given substance = given mass/molar mass
Therefore, no. Of moles of NaOH= x/40
Since, molarity = number of moles of solute/ volume of solution in lit.
Hence, 0.5 = (x/40)/(500/1000)
Solving this we get x= 10g
Hence, 10g of NaOH should be taken to obtain a 0.5 M solution of volume 500 mL.
I hope I could explain the numerical well and help you.
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