Question

Caculate the volume of 64g CH4 at STP

Answer 1

Explanation:

volume =89.6lit

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Answer 2

Answer:

89.6 L

Explanation:

Any 1 mole of gas at stp occupies 22.4 L

So 16g of CH4 occupies 22.4 L at stp

16 g of CH4 ----- 22.4L

64 g  --------- ?

= 64x22.4L/16

=4x22.4L

The Ans is 89.6 L

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