Question

caculate the weights of following
1)0.1mole sucrose b)0.1 Na2Co3
3)0.5 mole Gyspum​

Answer 1

1) sucrose is C12H22O11

molecular mass = 342

1 mole = 342 g

0.1mole= x g

x = 0.1 × 342

= 34.2 g

2) Na2CO3

molecular mass= 106

1 mole = 106 g

0.1mole= x g

x= 10.6 g

3) gypsum is CaSO4.2H2O

molecular mass = 172

1 mole = 172 g

0.5mole= x g

x = 0.5 × 172

= 86 g