Question

Caculatethe volume of47.0 cm3 of a gas at 27 ° C would occupies at 22°C at constant pressure​

Answer 1

It should be done by using charle’s law.
The formula is V1/T1 = V2/T2

Answer 2

Given:

Volume = 47.0$cm^{3}$

Initial temperature = 27°c

Final temperature = 22°c

To Find:

The volume of the gas at 22°c

Solution:

We can solve this numerical problem by using the following process.

Now,

Initial volume $V_{1}$ = 47.0$cm^{3}$

Initial temperature $T_{1}$ = 27°c

Final temperature $T_{2}$ = 22°c

Final volume $V_{2}$ = ?

According to Charle's Gas Law, we get the following expression:

$\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }$

$\frac{47}{27}=\frac{V_{2} }{22}$

$V_{2}=\frac{(47)(22)}{27}$

$V_{2}=38.29cm^{3}$

Hence, the volume of the gas at 22°c is 38.29cm³