Cadimium amalgam is obtained by the electroysis of a solution of cadimiun chloride using a mercury electrode. for how long should electrolysis be carried out to prepare 12% by weight cadimium amalgam using 44 grams of mercury and a current of 5 amperes?
Answers
Answer:
Explanation:
its a very easy question
in this first differentiate into anion and cation
here anion is cl- and cation is cd+2 and as hg is a attakable electrode it will also participate in reaction
first it makes bond with cd+2 and forms cdhg2
after make oxidation of cdhg2 by removing 2 e
the reaction is as cdhg2 = cdgh+2 + 2e
and reaction at cathode
2cl- = cl2+2e
reverse the reaction which i have written
cdhg2 +2 + 2e = cdhg2
here given cdhg2 is 12 percent by weight of solution of cdcl2 using 44 grams mercury
weight of cdhg2 / weight of solution of cdcl2 and 44 grams mercury = 12 percent
weight of cdhg2 = 12/100 * weight of solution containing cdcl2 and 44 grams hg
weight of cdhg2 = 12/100*227.5
weight of cdhg2= 27.3 g
equivalent of cdhg2 = 5t/96500
moles*f = 5t/96500
0.05*2 = 5t/96500
0.1 = 5t /96500
9650=5t
1930sec =t