Question

Caesium chloride forms simple cubic lattice in which cs+ ions are the corners and cl ion is in the center. The cation-anion contact occurs along the body diagonal of the unit cell. (the body diagonal starts at one corners and then runs through the center of the cell to the opposite corner.). The length of the edge of the unit cell is 412.3 pm. The cl ion has a radius of 181 pm. Calculate the radius of cs+ ion.(in pm)

Answer 1

Answer:

I not understand your question plzzz ask again pkkk