Question

cal acquires a velocity of 72 kilometre per hour in 20 seconds starting from the rest find (a)the acceleration
(b) the distance travelled by the car ​

Answer 1

Answer:

v=72 km/h= 3600

72×1000 =20 m/s

Acceleration a= tv−u

= 10s(20−0) ms −1

=2 ms −2

Answer 2

Answer:

Acceleration = 3.6m/s²

Distance travelled = 720m

Explanation:

initial velocity (u) = 0m/s

final velocity (v) = 72km/h = 20m/s

acceleration (a) = ?

distance (s) = ?

a. Acceleration (a) = $\frac{v - u}{t}$ (means that acceleration = change in velocity / time taken)

a = $\frac{72 - 0}{20}$ ... So, a = 3.6m/s²

b. Distance (s) = ut + ¹/₂ at²

s = (0*20) + 1/2 * 3.6 * 20 * 20

s = 36 * 20

So, s = 720m

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