Question

Cal no of molecules in of s8 present in 32 g of solid sulphur

Answer 1

Molar mass of sulphur =32

Therefore, molar mass of sulphur S8=32×8=256g/mol.

Number of moles=32/256=0.125moles

Therefore, number of molecules = Number of moles × Avogadro's number

$= 0.125 \times 6.022 \times 10 ^{23}$

$= 0.7527 \times 10 ^{23} molecules$

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 32g of solid sulpur contains

(6.022×10^23 /256 )32 molecules

= 0.75 × 10^23 molecules (approx)

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I hope, this will help you.☺

Thank you______❤

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