Question

cal. the masses of sugar and water required to prepare 250g of 25% solution of can sugar ?​

Answer 1

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$\rm{\underline{given-}}$

mass percent = 25

mass of solution= 250g

$\large\boxed{mass \: percent = \frac{mass \: of \: solute}{mass \: of \: solution} \times 100}$

$25 = \frac{mass \: of \: can \: sugar}{250} \times 100 \: \: \: (mass \: of \: cane)$

$= > \frac{25 \times (250g)}{100}$

$\large\boxed{62.5gram}$

and, mass of water

$= > 250 - 62.5$

$\large\boxed{187.5gram}$

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