Cal. the molality of ethanol solution in which mole fraction of water is 0.88?
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Answer:- 407.4m.
Solution:- Molality is moles of solute per kg of solvent. For the given problem, the solute is ethanol and solvent is water. The mole fraction of ethanol is given as 0.88.
We know that, the sum of mole fractions is 1. So, if the mole fraction of ethanol is 0.88 then mole fraction of water would be = 1 - 0.88 = 0.12
It's simply like we have 0.88 moles of ethanol and 0.12 moles of water. Since. mole fraction is moles divided by total moles.
For example, mole fraction of ethanol = \frac{mol of ethanol}{mol of ethanol+mol of water}molofethanol+molofwatermolofethanol
Let's convert 0.12 moles of water to g and then kg:
0.12mol(\frac{18.02g}{1mol})(\frac{1kg}{1000g})0.12mol(1mol18.02g)(1000g1kg)
= 0.00216 kg
So, the molality of the solution = \frac{0.88mol}{0.00216kg}0.00216kg0.88mol
= 407.4m
So, the molality of the solution is 407.4 m.
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Solution:- Molality is moles of solute per kg of solvent. For the given problem, the solute is ethanol and solvent is water. The mole fraction of ethanol is given as 0.88.
We know that, the sum of mole fractions is 1. So, if the mole fraction of ethanol is 0.88 then mole fraction of water would be = 1 - 0.88 = 0.12
It's simply like we have 0.88 moles of ethanol and 0.12 moles of water. Since. mole fraction is moles divided by total moles.
For example, mole fraction of ethanol = \frac{mol of ethanol}{mol of ethanol+mol of water}molofethanol+molofwatermolofethanol
Let's convert 0.12 moles of water to g and then kg:
0.12mol(\frac{18.02g}{1mol})(\frac{1kg}{1000g})0.12mol(1mol18.02g)(1000g1kg)
= 0.00216 kg
So, the molality of the solution = \frac{0.88mol}{0.00216kg}0.00216kg0.88mol
= 407.4m
So, the molality of the solution is 407.4 m.
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