calaulate number of molecules and number of atoms in present in 11.2litter of oxygen
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no of molecules=3.011× 10^ 23
no of atoms= 6.022 ×10^23
Explanation:
22.4 L= 1mole =6.022 × 10^23 molecules
11.2L=0.5 mole= 3.011×10^23 molecules
Each molecule has 2 atoms
No of atoms= 2×3.011×10^23.
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