Question

Calccelate what valome of co2 will be liberated
by burning 6 gm of C andO2​

Answer 1

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The volume of one mole of CO2 produced is 24 dm^3 at room temperature and pressure. Alternatively, if your reaction took place at standard temperature and pressure (273 K, 1 atm), then the molar volume is 22.4 dm^3.

Answer 2

Explanation:

C+O2-->CO2

12g Co2 reacts with 32 g O2 to produce 44gCO2

6g will react with 16g O2 to give 22g CO2

44gCO2 contains 22.4L

22g CO2 contains 11.2L volume at STP

22.4L contains 6.022* 10^23

So 11.2L will contain 6.022 * 10^23/2=3.011*10^23 molecules of CO2