calcium carbonate in heated an open vessel. What would have been observation from the following statements?
a. Mass of the reactants is more than mass of the products b. Mass of the products is more than mass of the reactants c. Masses of the products and reactants are equal
d. None of the above
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The law of conservation of mass is a fundamental law and is applicable everywhere.. Here as well the law is valid as the mass of reactants and mass of the products will be the same. But since the reaction is carried out in an open container, CO2 which is one of the products of the reaction will leave the vessel and hence the calculated mass will not be the same as reactants
durgeshsinghrajput30:
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We are not asked calculated mass just it is given mass of product and reactants will be same and as co2 is a product we need to add its mass
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calcium carbonate decomposes to form Calcium oxide and carbon dioxide.
CaCO3-> CaO + CO2
So,Masses of the products and reactants are equal
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Hey are you sure as it is a open vessel
ya
bcoz we dont consider here molecular mass like one atom of oxygen =16
But the co2 will not librate
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