Calcium carbonate is decomposed by HCl as follows: CaCO3 + 2HCl → CaCl2 + H2O + CO2 a. Calculate the mass of water produced by the reaction of 4 mol. Of CaCO3 with 4 mol. Of HCl. b. Define limiting reagent. c. If 2 mol. Of CaCO3 produces 40 L of CO2 at NTP upon reaction with excess HCl, what is the % age yield of the reaction. d. If 250 g. of CaCO3 upon reaction with excess HCl gives 222 g. of CaCl2, what is the % age purity of CaCo3?
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''40" (and any subsequent words) was ignored because we limit queries to 32 words.
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CaCO3 + 2HCl -----> CaCl2 + H2O + CO2.
2.5g? g
Mass of CaCO3= 40+12+3(16)=52+ 48= 100.
Molar mass of CaCO3=100g.
Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111.
Molar mass of CaCl2=111g.
Mass of CaCO3 (g) Mass of CaCl2 (g)
For 100g of CaCO
3
, 111g of CaCl_2$$ is formed.
let for 2.5g of CaCO
3
, x g of CaCl
2
is formed.
Thus, by cross multiplication,
x=111×2.5/100=2.775g=2.78g.
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