calcium carbonate react with Aqua HCL to give cacl2 and CO2 according to the reaction caco3 + 2 HCL cacl2 + CO2 + H2O what mass of caco3 is required to react completely with 50 ml of 0.5 m HCL
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Answer: 1.24g
Explanation:
vol of Hcl=50ml
molarity of 50ml Hcl=0.5M
1 M of HCl=36.5g (cl=35.5 and h=1)
0.5M of Hcl=x
x=36.5x0.5= 18.25g
mass of Hcl in 50mL= 36.5x0.5x50/ 1000=0.912g
2x36.5 (2 moles of Hcl)---> 100g of CaCo3
0.912g of Hcl--->x Caco3
x=100x0.912/73= 1.24g
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