Question

Calcium carbonate reacts with 50 mL of 0.2 M HCI
as per the following reaction,
CaCO3 + 2HCl(aq) +
CaCl2(aq) + CO2(g) + H2O(1)
The mass of CaCO3 required to completely react with
the given HCl is
(a) 1.009
(b) 0.10 g
(C) 0.50 g
(d) 5.00 g
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Answer 1

Answer:

sorry I didn't know the answer