Calcium carbonate reacts with aqueous HCI to give CaC12 anid CO2 according to the reaction CaCO₂ (s) + 2 HC jagl+CaCl(aq)-CD. (8) + H₂O(l) [12] if 500g Caco, reacts with 500mL 0.5 M HCI then how many gram of calcium chloride would be formed?
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Answer:
The mass of HCl is 10000.75×36.5×25=0.684g.
1 mole of calcium carbonate reacts with 2 moles of HCl.
Hence, the mass of calcium carbonate that will react completely with 0.684 g of HCl is
2×36.5100×0.684=0.937g
Explanation:
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